(4cos^2x+3cosx-2)=0

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Solution for (4cos^2x+3cosx-2)=0 equation:


Simplifying
(4cos2x + 3cosx + -2) = 0

Reorder the terms:
(-2 + 3cosx + 4cos2x) = 0

Remove parenthesis around (-2 + 3cosx + 4cos2x)
-2 + 3cosx + 4cos2x = 0

Solving
-2 + 3cosx + 4cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 3cosx + 2 + 4cos2x = 0 + 2

Reorder the terms:
-2 + 2 + 3cosx + 4cos2x = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 3cosx + 4cos2x = 0 + 2
3cosx + 4cos2x = 0 + 2

Combine like terms: 0 + 2 = 2
3cosx + 4cos2x = 2

Reorder the terms:
-2 + 3cosx + 4cos2x = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 3cosx + 4cos2x = 0

The solution to this equation could not be determined.

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